Classification – Odd one out (multiples of 17) Three of these integers are exact multiples of 17. Identify the number that is not a multiple of 17 and mark it as the odd one out.

Introduction / Context:Classification items frequently use a common factor to bind most options, leaving one that does not share the factor. Rapid factor recognition reduces computation time and errors.

Given Data / Assumptions:

• Options: 119, 136, 147, 153
• Target property: divisibility by 17

Concept / Approach:Compute or recall simple multiples of 17: 17 * 7 = 119, 17 * 8 = 136, 17 * 9 = 153. Any number not matching this pattern is the outlier.

Step-by-Step Solution:119 = 17 * 7 → divisible by 17.136 = 17 * 8 → divisible by 17.153 = 17 * 9 → divisible by 17.147 ÷ 17 = 8 remainder 11 → not divisible by 17.

Verification / Alternative check:Mental arithmetic confirms that the sequence 119, 136, 153 are consecutive multiples of 17; 147 sits between 136 and 153 but does not align with 17k for any integer k.

Why Other Options Are Wrong:

• 119: Clean multiple of 17.
• 136: Clean multiple of 17.
• 153: Clean multiple of 17.
• None of these: A single odd one out exists (147).

Common Pitfalls:Assuming proximity implies membership in the sequence. Being near a multiple does not satisfy divisibility.

Final Answer:147