Odd One Out — Among the 4-letter strings TPOC, BKDF, OLTF, and BILQ, detect the one that does not contain any vowel (or equivalently, differs by vowel presence).

Introduction / Context:Letter-classification items commonly use vowel vs consonant structure as an underlying rule. The task is to find the single string that breaks or uniquely satisfies the rule.

Given Data / Assumptions:

• Strings: TPOC, BKDF, OLTF, BILQ.
• Vowels considered: A, E, I, O, U.

Concept / Approach:Check each string for the presence or absence of vowels.

Step-by-Step Solution:TPOC: contains O (a vowel).BKDF: B, K, D, F are all consonants; no vowel present.OLTF: contains O (a vowel).BILQ: contains I (a vowel).Exactly one string has no vowel: BKDF.

Verification / Alternative check:Re-scan each letter set; only BKDF lacks A, E, I, O, U.

Why Other Options Are Wrong:

• TPOC: has O.
• OLTF: has O.
• BILQ: has I.

Common Pitfalls:Overlooking the letter I in BILQ or treating Y as a vowel in this context.

Final Answer:BKDF