Odd One Out — Among the 4-letter strings TPOC, BKDF, OLTF, and BILQ, detect the one that does not contain any vowel (or equivalently, differs by vowel presence).

Difficulty: Easy

Correct Answer: BKDF

Explanation:


Introduction / Context:
Letter-classification items commonly use vowel vs consonant structure as an underlying rule. The task is to find the single string that breaks or uniquely satisfies the rule.



Given Data / Assumptions:

  • Strings: TPOC, BKDF, OLTF, BILQ.
  • Vowels considered: A, E, I, O, U.


Concept / Approach:
Check each string for the presence or absence of vowels.



Step-by-Step Solution:
TPOC: contains O (a vowel).BKDF: B, K, D, F are all consonants; no vowel present.OLTF: contains O (a vowel).BILQ: contains I (a vowel).Exactly one string has no vowel: BKDF.



Verification / Alternative check:
Re-scan each letter set; only BKDF lacks A, E, I, O, U.



Why Other Options Are Wrong:

  • TPOC: has O.
  • OLTF: has O.
  • BILQ: has I.


Common Pitfalls:
Overlooking the letter I in BILQ or treating Y as a vowel in this context.



Final Answer:
BKDF

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