From 12 points in the plane, of which 7 are collinear and the rest are in general position, how many distinct triangles can be formed by choosing any 3 points?

Introduction / Context:
Any 3 non-collinear points form a triangle. Triples that lie on the same straight line are degenerate and must be excluded.

Given Data / Assumptions:

• Total points = 12.
• A set of 7 points are collinear; the remaining 5 are not collinear with them as a group.

Concept / Approach:
Total triples minus degenerate triples along the 7-point line gives the count of triangles.

Step-by-Step Solution:

Verification / Alternative check:
Any triple including at least one of the 5 off-line points is non-collinear with the 7-point line, hence valid.

Why Other Options Are Wrong:
175, 115, 105 subtract too much or use the wrong base total.

Common Pitfalls:
Missing that only triples entirely within the 7-point collinear set fail to form a triangle.

Final Answer:
185