A library has a copies of one title, b copies of each of two titles, c copies of each of three titles, and a single copy of d distinct titles (one each). In how many ways can all these books be arranged in a row? (Indistinguishable copies of the same title.)

Introduction / Context:This is a multiset permutation problem. We have totals of identical copies by title. The denominator multiplies factorials of each title’s multiplicity.

Given Data / Assumptions:

• Total books N = a + 2b + 3c + d.
• Indistinguishable copies for identical titles.
• Two titles have b copies each ⇒ (b!)^2; three titles have c copies each ⇒ (c!)^3.

Concept / Approach:Number of distinct arrangements of N items with groups of indistinguishable items is N! divided by the product of factorials of each group size.

Step-by-Step Solution:

Verification / Alternative check:Setting b = c = 0 reduces to (a + d)! / a!, consistent with a identical copies of one title and d singletons.

Why Other Options Are Wrong:Options lacking (b!)^2 or (c!)^3 fail to account for indistinguishability across multiple titles of equal multiplicity.

Common Pitfalls:Forgetting that “two books with b copies each” contributes (b!)^2 and “three books with c copies each” contributes (c!)^3.

Final Answer:(a + 2b + 3c + d)! / {a! (b!)2 (c!)3}