Difficulty: Easy
Correct Answer: 40
Explanation:
Introduction / Context:
We form three-digit numbers from a given set with distinct digits and a numeric bound (< 400). The hundreds place determines the bound handling; then we count permutations for the remaining places.
Given Data / Assumptions:
S = {2, 3, 4, 5, 7, 9}; digits cannot repeat; number < 400.
Concept / Approach:
Constrain the hundreds digit first. Only 2 or 3 keep the number below 400. For each choice of hundreds, count permutations of tens and units from the remaining digits.
Step-by-Step Solution:
Verification / Alternative check:
Enumerating quickly for hundreds=2 and 3 confirms symmetry and count.
Why Other Options Are Wrong:
20 counts only one hundreds choice; 80 or 120 overcount beyond the < 400 constraint.
Common Pitfalls:
Accidentally including 4,5,7,9 as hundreds, which violates the bound.
Final Answer:
40
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