Difficulty: Easy
Correct Answer: 40
Explanation:
Introduction / Context:We form three-digit numbers from a given set with distinct digits and a numeric bound (< 400). The hundreds place determines the bound handling; then we count permutations for the remaining places.
Given Data / Assumptions:S = {2, 3, 4, 5, 7, 9}; digits cannot repeat; number < 400.
Concept / Approach:Constrain the hundreds digit first. Only 2 or 3 keep the number below 400. For each choice of hundreds, count permutations of tens and units from the remaining digits.
Step-by-Step Solution:
Hundreds choices: 2 options (2 or 3)For a fixed hundreds digit: tens = 5 choices, units = 4 choices (distinctness)Per hundreds choice: 5 * 4 = 20 numbersTotal = 2 * 20 = 40Verification / Alternative check:Enumerating quickly for hundreds=2 and 3 confirms symmetry and count.
Why Other Options Are Wrong:20 counts only one hundreds choice; 80 or 120 overcount beyond the < 400 constraint.
Common Pitfalls:Accidentally including 4,5,7,9 as hundreds, which violates the bound.
Final Answer:40
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