Three-digit numbers from S = {2, 3, 4, 5, 7, 9} less than 400: How many distinct-digit three-digit numbers < 400 can be formed?

Difficulty: Easy

Correct Answer: 40

Explanation:


Introduction / Context:
We form three-digit numbers from a given set with distinct digits and a numeric bound (< 400). The hundreds place determines the bound handling; then we count permutations for the remaining places.


Given Data / Assumptions:
S = {2, 3, 4, 5, 7, 9}; digits cannot repeat; number < 400.


Concept / Approach:
Constrain the hundreds digit first. Only 2 or 3 keep the number below 400. For each choice of hundreds, count permutations of tens and units from the remaining digits.


Step-by-Step Solution:

Hundreds choices: 2 options (2 or 3)For a fixed hundreds digit: tens = 5 choices, units = 4 choices (distinctness)Per hundreds choice: 5 * 4 = 20 numbersTotal = 2 * 20 = 40


Verification / Alternative check:
Enumerating quickly for hundreds=2 and 3 confirms symmetry and count.


Why Other Options Are Wrong:
20 counts only one hundreds choice; 80 or 120 overcount beyond the < 400 constraint.


Common Pitfalls:
Accidentally including 4,5,7,9 as hundreds, which violates the bound.


Final Answer:
40

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