Difficulty: Easy
Correct Answer: fanout
Explanation:
Introduction / Context:
Fanout defines how many standard logic inputs a single gate output can drive while still meeting valid logic level specifications. It is crucial in digital system loading and buffering decisions.
Given Data / Assumptions:
Concept / Approach:
Fanout is the ratio of the maximum source/sink current capability of an output to the input current required by a standard load. In classic TTL, an output characterized to drive ten standard inputs has a fanout of 10. Staying within fanout preserves VOH/VOL margins and timing integrity.
Step-by-Step Solution:
Identify parameter: number of inputs driven per output.Interpret “ten loads”: equals fanout of 10.Conclude mapping: the given statement is the fanout specification.
Verification / Alternative check:
Datasheets specify I_OH/I_OL and I_IH/I_IL; fanout_low ≈ I_OL / I_IL and fanout_high ≈ I_OH / I_IH. Typical older TTL values support fanout around ten.
Why Other Options Are Wrong:
Noise immunity: relates to voltage margins, not loading count.Power dissipation: describes energy use, not drive capability.Propagation delay: timing parameter, not loading quantity.
Common Pitfalls:
Ignoring capacitive loading and trace fanout which affect edges and timing even within dc fanout limits. Consider buffering for high-speed nets.
Final Answer:
fanout
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