Square wave harmonics: A square wave has a period of 60 µs. What is the frequency of the first odd harmonic beyond the fundamental?

Difficulty: Easy

Correct Answer: 50 kHz

Explanation:


Introduction / Context:
Square waves contain only odd harmonics (1st, 3rd, 5th, … multiples of the fundamental frequency). The 'first odd harmonic' beyond the fundamental is the 3rd harmonic. Recognizing this is essential in spectra, filtering, and pulse-shaping design.


Given Data / Assumptions:

  • Period T = 60 µs → fundamental f1 = 1/T.
  • Square wave with standard Fourier content (odd harmonics only).


Concept / Approach:
Compute f1, then multiply by 3 to obtain the 3rd harmonic. Convert microseconds to seconds carefully to avoid order-of-magnitude mistakes.


Step-by-Step Solution:

f1 = 1 / (60 × 10^-6 s) ≈ 16.666… kHz.3rd harmonic: f3 = 3 * f1 ≈ 3 * 16.666… kHz ≈ 50 kHz.Therefore, the first odd harmonic beyond the fundamental is ≈ 50 kHz.


Verification / Alternative check:
Quick check: If T = 60 µs, then 1/T = 16.67 kHz; triple is exactly 50.0 kHz. This aligns with the classic harmonic structure of square waves.


Why Other Options Are Wrong:

  • 33.33 kHz: That would be 2 * 16.67 kHz (an even harmonic, which is absent).
  • 500 kHz or 5 kHz: Not related to 3 × 16.67 kHz; they are an order of magnitude off.


Common Pitfalls:

  • Assuming the 'first harmonic' means the fundamental itself; here it explicitly asks for the first odd harmonic beyond the fundamental (the 3rd).


Final Answer:
50 kHz

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