Square wave harmonics: A square wave has a period of 60 µs. What is the frequency of the first odd harmonic beyond the fundamental?
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A5 kHz
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B50 kHz
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C500 kHz
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D33.33 kHz
Answer
Correct Answer: 50 kHz
Explanation
Introduction / Context:Square waves contain only odd harmonics (1st, 3rd, 5th, … multiples of the fundamental frequency). The 'first odd harmonic' beyond the fundamental is the 3rd harmonic. Recognizing this is essential in spectra, filtering, and pulse-shaping design.
Given Data / Assumptions:
- Period T = 60 µs → fundamental f1 = 1/T.
- Square wave with standard Fourier content (odd harmonics only).
Concept / Approach:Compute f1, then multiply by 3 to obtain the 3rd harmonic. Convert microseconds to seconds carefully to avoid order-of-magnitude mistakes.
Step-by-Step Solution:
f1 = 1 / (60 × 10^-6 s) ≈ 16.666… kHz.3rd harmonic: f3 = 3 * f1 ≈ 3 * 16.666… kHz ≈ 50 kHz.Therefore, the first odd harmonic beyond the fundamental is ≈ 50 kHz.Verification / Alternative check:Quick check: If T = 60 µs, then 1/T = 16.67 kHz; triple is exactly 50.0 kHz. This aligns with the classic harmonic structure of square waves.
Why Other Options Are Wrong:
- 33.33 kHz: That would be 2 * 16.67 kHz (an even harmonic, which is absent).
- 500 kHz or 5 kHz: Not related to 3 × 16.67 kHz; they are an order of magnitude off.
Common Pitfalls:
- Assuming the 'first harmonic' means the fundamental itself; here it explicitly asks for the first odd harmonic beyond the fundamental (the 3rd).
Final Answer:50 kHz