Phase comparison from zero crossings: One sine wave crosses zero (positive-going) at 15°, and a second sine wave crosses zero (positive-going) at 55°. What is the phase angle difference between the two waveforms?

Difficulty: Easy

Correct Answer: 40°

Explanation:


Introduction / Context:
Zero-crossing timing is a quick way to infer phase shift between two sinusoids of the same frequency. The positive-going zero crossing is a clean reference because amplitude differences do not affect the crossing instant, only phase does. This is fundamental in AC measurements, synchronization, and phasor analysis.


Given Data / Assumptions:

  • Sine wave A: positive-going zero at 15°.
  • Sine wave B: positive-going zero at 55°.
  • Both have the same frequency and are measured within the same cycle reference.


Concept / Approach:
For equal-frequency sinusoids, phase difference equals the angular separation between corresponding features (here, positive-going zeros). Subtract the angles, taking the smaller absolute separation modulo 360° if needed.


Step-by-Step Solution:

Δφ = 55° − 15° = 40°.This is the phase by which the second waveform leads the first.


Verification / Alternative check:
Plotting or imagining the sine waves confirms waveform B reaches zero later (at a higher angle), indicating a 40° lead relative to the 15° reference.


Why Other Options Are Wrong:

  • 0°: Would require identical crossing angles.
  • 45°: Not equal to the given separation.
  • none of the above: Incorrect since 40° is directly obtained.


Common Pitfalls:

  • Using negative-going zeros or mixing degree/radian units.
  • Forgetting that only equal-frequency waves have a fixed phase difference.


Final Answer:
40°

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