Effective (rms) value of a sinusoid: The effective value of a sine wave, expressed relative to its peak value, is equal to which of the following?

Difficulty: Easy

Correct Answer: both 0.707 of peak voltage and sin 45° of peak voltage

Explanation:


Introduction:
Root-mean-square (rms) value is the DC-equivalent heating value of an AC waveform. For a pure sine wave, rms has a fixed ratio to peak (maximum) and to peak-to-peak, which is essential when converting between datasheet ratings, scope measurements, and power calculations.


Given Data / Assumptions:

  • Ideal sinusoidal waveform.
  • We want rms in terms of peak.


Concept / Approach:

For a pure sine: Vrms = Vp / √2. Numerically, 1 / √2 ≈ 0.707106. Also, sin 45° = √2 / 2 ≈ 0.707106. Thus 0.707 of peak and sin 45° of peak are equal statements. Note that 0.636 of peak is the average of a full-wave rectified sine, not the rms of a pure sine.


Step-by-Step Solution:

Start with Vrms = Vp / √2.Compute numeric factor: 1 / √2 ≈ 0.707.Recognize trigonometric identity: sin 45° = √2 / 2 ≈ 0.707.Therefore Vrms is both 0.707 * Vp and sin 45° * Vp.


Verification / Alternative check:

Check with Vp = 10 V: Vrms = 10 / √2 ≈ 7.071 V; sin 45° * 10 V gives the same, confirming equivalence.


Why Other Options Are Wrong:

  • 0.636 of peak voltage: This is the average of a full-wave rectified sine (2/π), not rms.
  • 0.5 of peak voltage: No standard sinusoidal relation yields this as rms.


Common Pitfalls:

  • Mixing up average and rms for rectified signals.
  • Confusing peak with peak-to-peak (Vp-p = 2 * Vp).


Final Answer:

both 0.707 of peak voltage and sin 45° of peak voltage

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