Difficulty: Easy
Correct Answer: 12 kHz
Explanation:
Introduction / Context:
The instantaneous rate of change of a sine wave (slope or dv/dt) scales with angular frequency. Higher frequency signals swing through their cycles faster and therefore exhibit greater maximum slope. This concept underpins bandwidth limits, slew-rate considerations, and filter behavior.
Given Data / Assumptions:
Concept / Approach:
For v(t) = Vp sin(2π f t), the maximum slope is dv/dt|max = 2π f Vp. With fixed amplitude, slope increases linearly with f. Therefore, any frequency lower than 15 kHz has a lower maximum rate of change.
Step-by-Step Solution:
Verification / Alternative check:
Compute the ratio of slopes: dv/dt|max(15k)/dv/dt|max(12k) = 15/12 = 1.25 > 1, confirming higher rate at 15 kHz for equal amplitudes.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
12 kHz
Discussion & Comments