Difficulty: Easy
Correct Answer: 12 kHz
Explanation:
Introduction / Context:The instantaneous rate of change of a sine wave (slope or dv/dt) scales with angular frequency. Higher frequency signals swing through their cycles faster and therefore exhibit greater maximum slope. This concept underpins bandwidth limits, slew-rate considerations, and filter behavior.
Given Data / Assumptions:
Concept / Approach:For v(t) = Vp sin(2π f t), the maximum slope is dv/dt|max = 2π f Vp. With fixed amplitude, slope increases linearly with f. Therefore, any frequency lower than 15 kHz has a lower maximum rate of change.
Step-by-Step Solution:
Identify frequencies lower than 15 kHz among options.Only 12 kHz is less than 15 kHz; the others are higher.Hence, the 15 kHz sine changes faster than a 12 kHz sine.Verification / Alternative check:Compute the ratio of slopes: dv/dt|max(15k)/dv/dt|max(12k) = 15/12 = 1.25 > 1, confirming higher rate at 15 kHz for equal amplitudes.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:12 kHz
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