Six-member row arrangement: U is to the left of V but to the right of W; W is to the right of X; Y is to the right of Z; and Z is to the left of X. Who are the two members sitting exactly in the middle positions?

Introduction / Context:
This seating-arrangement problem gives multiple left–right constraints for six members U, V, W, X, Y, Z seated in a single row. The goal is to determine the two people who occupy the middle two seats.

Given Data / Assumptions:

• U is left of V but right of W.
• W is right of X.
• Y is right of Z.
• Z is left of X.
• Exactly six distinct people; exactly one per seat.

Concept / Approach:
Chain the inequalities to build a partial order. From X < W < U < V and Z < X plus Y > Z, assemble a consistent left-to-right lineup satisfying all relations, then read off the two middle positions.

Step-by-Step Solution:
From W right of X and U right of W and V right of U: X < W < U < V.Also Z left of X (Z < X) and Y right of Z (Z < Y).One valid order that fits all is: Z, Y, X, W, U, V.The middle seats (3rd and 4th) are X and W.

Verification / Alternative check:
Another valid order is Z, X, W, U, Y, V; but that violates “Y right of Z” if Y falls left of Z. The chosen order satisfies all four relations simultaneously.

Why Other Options Are Wrong:

• ZY: these are at the left in our valid lineup, not the middle.
• UV or WV: positions (4,5) or (4,5) respectively, not the two center seats.
• None of these: incorrect because XW is attainable.

Common Pitfalls:
Forgetting that “left of” and “right of” are transitive and that Y only needs to be to the right of Z, not necessarily to the far right.

Final Answer:
XW