Five students in a row — first from the left? T is on the right of Z. M is on the left of Z but on the right of L. T is on the left of Q. Who is first from the left end of the row?

Introduction / Context:We must place five students linearly and identify the leftmost person.

Given Data / Assumptions:

• T right of Z.
• M left of Z but right of L ⇒ L < M < Z.
• T left of Q ⇒ T < Q.

Concept / Approach:Combine chains: from L < M < Z and T right of Z, we get L < M < Z < T. With T < Q, extend to L < M < Z < T < Q.

Step-by-Step Solution:The only linearization satisfying all constraints is L, M, Z, T, Q (left→right).Therefore, the first from the left is L.

Verification / Alternative check:Attempting to move any element left/right breaks at least one inequality (e.g., placing Z before M violates L < M < Z).

Why Other Options Are Wrong:Z/Q/T cannot be leftmost without contradicting the chain; only L fits.

Final Answer:L