Schmitt-trigger conditioning of a 60 Hz reference: In a digital clock front-end, a 60 Hz mains-derived waveform is passed through a Schmitt-trigger buffer to create clean logic transitions at the rate of ________.

Difficulty: Easy

Correct Answer: 60 pps

Explanation:


Introduction / Context:
Digital clocks often derive timing from either a crystal oscillator or the AC mains frequency (50/60 Hz). When using the mains, the sinusoidal voltage must be isolated, scaled, and squared up into clean logic pulses. A Schmitt trigger provides hysteresis to convert the slowly changing waveform into sharp digital edges.



Given Data / Assumptions:

  • Input frequency is 60 Hz.
  • A Schmitt trigger outputs rail-to-rail logic-level pulses on threshold crossings.
  • No frequency division or multiplication is performed in the Schmitt stage itself.


Concept / Approach:
The Schmitt trigger does not change the fundamental frequency; it improves edge quality and noise immunity. Therefore, its output toggles at the same rate as the input fundamental, producing a pulse train at 60 pulses per second (pps), suitable for gating counters or for further division to 1 pps.



Step-by-Step Solution:

Feed the isolated 60 Hz waveform into the Schmitt buffer.As the input crosses the upper threshold, the output toggles HIGH; crossing the lower threshold toggles LOW.This produces square pulses synchronized to 60 Hz.Choose 60 pps as the output rate.


Verification / Alternative check:
Oscilloscope captures show one complete output cycle per 60 Hz input cycle after the Schmitt stage.



Why Other Options Are Wrong:

1 pps: Requires a divider chain.100 pps / 600 pps: Not produced by a simple Schmitt trigger from a 60 Hz input.


Common Pitfalls:
Mislabeling Schmitt outputs as sine pulses; ignoring isolation and safety when sampling the mains waveform.


Final Answer:
60 pps

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