Difficulty: Medium
Correct Answer: NAND columns
Explanation:
Introduction / Context:Matrix keypads are scanned by driving or reading rows and columns. In active-low schemes, a pressed key pulls one column line low while others remain high. To capture a valid keypress and prevent chatter or ghosting, many encoders assert a “freeze” (or latch) signal only when exactly one column indicates activation.
Given Data / Assumptions:
Concept / Approach:NAND gates are convenient for detecting combinations and ensuring that only one low is present. For example, by appropriately combining signals (possibly after inversion), a NAND network can produce a HIGH (asserted) freeze only when one column is low and all others are high. Additional gating can reject two-or-more simultaneous lows.
Step-by-Step Solution:
Define the one-hot condition for columns C3..C0 (active-low): exactly one Ci = 0 and the rest = 1.Construct logic using NANDs (and inverters where needed) to detect this condition.Drive the freeze latch with the NAND network output to hold the detected key code until release.Debounce and time-qualify as necessary.Verification / Alternative check:Truth-table simulation confirms freeze = 1 for one-low cases and 0 for none or multiple-low cases. Gate-level schematics from synthesis will show NAND-rich implementations for compactness.
Why Other Options Are Wrong:
CASE structure: A behavioral construct; implementation still maps to gates like NAND/NOR.freeze function: Descriptive term, not a gate-level implementation.BCD counter: Counts digits; unrelated to one-hot detection.Common Pitfalls:Allowing ghost keys due to shared row/column paths; failing to debounce; not masking multiple simultaneous keypresses.
Final Answer:NAND columns
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