Difficulty: Medium
Correct Answer: Increasing the feed rate
Explanation:
Introduction / Context:
Material removal rate (MRR) is a key productivity metric in machining. However, productivity must be balanced against tool life. This question examines which parameter change most effectively boosts MRR while holding the allowed tool life constant, a classic optimization trade-off in manufacturing engineering.
Given Data / Assumptions:
Concept / Approach:
Cutting speed V has a strong influence on tool life through the Taylor exponent n (often 0.1–0.3 for HSS/carbide). Feed and depth also affect life, but typically with smaller exponents in extended models. For a fixed life, increasing V is restricted; increasing feed (and, secondarily, depth) raises MRR markedly with less penalty to life compared with speed increases.
Step-by-Step Solution:
Start from Taylor: V * T^n = C ⇒ at constant T, V is essentially fixed by C and n.Express MRR: MRR ∝ f * d * Vw. If Vw (related to V) cannot increase much at constant T, target f and d.Feed directly multiplies MRR and is usually the first lever before depth for chip-load efficiency and stable cutting.Therefore, increasing feed rate maximizes MRR under the same tool life constraint.
Verification / Alternative check:
In practical shop economics, the “maximum production rate” or “minimum cost” settings derive from balanced f–d–V; charts show that modest speed with higher feed often yields high MRR at acceptable tool life.
Why Other Options Are Wrong:
(a) Increasing cutting speed sharply reduces tool life at constant f, d; not allowed under the constraint. (b) Decreasing speed reduces MRR. (c) Increasing depth of cut helps MRR but is usually the second lever after feed and may hit power/rigidity limits sooner. (e) Nose radius affects finish and tool strength more than MRR directly.
Common Pitfalls:
Assuming speed is the only path to higher MRR; ignoring machine power, chatter, and surface roughness limits when raising feed.
Final Answer:
Increasing the feed rate
Discussion & Comments