Taylor’s tool life relationship For cutting speed V (m/min) and tool life T (min), which form expresses the classical Taylor equation (n is the tool–work exponent, C is a constant)?

Difficulty: Easy

Correct Answer: V T^n = C

Explanation:


Introduction / Context:
Taylor’s tool life equation is foundational in machining economics. It relates cutting speed to tool life and underpins choices for minimum cost, maximum production rate, and given-life cutting conditions.



Given Data / Assumptions:

  • Speed V in m/min; life T in minutes.
  • n (0.1–0.3 typical) depends on tool/work material system.
  • C is an empirical constant for a given setup.


Concept / Approach:
The canonical form is V T^n = C. Log-transforming gives log V = log C − n log T, a straight line often used for plotting speed–life data and extracting n and C from tests.



Step-by-Step Solution:
Recall standard form: V T^n = C.Check dimensional and empirical consistency: V decreases as T increases for n > 0.Select the option matching this relationship.



Verification / Alternative check:
Doubling tool life requires reducing speed by factor 2^(−1/n), consistent with experience.



Why Other Options Are Wrong:
(a), (c), and (d) misplace the exponent on V or T. (e) is not the classical Taylor form.



Common Pitfalls:
Confusing n placement or assuming linear V–T directly; the relationship is a power law, not linear.



Final Answer:
V T^n = C


More Questions from Production Engineering

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion