Difficulty: Easy
Correct Answer: During simultaneous infection of a host cell by two viruses with homologous genomes
Explanation:
Introduction / Context:Viruses evolve rapidly through mutation and recombination. Recombination requires co-presence of related genomes in the same host cell, enabling template switching or segment reassortment, depending on the virus type.
Given Data / Assumptions:
Concept / Approach:
When two related viruses infect the same cell, replication machinery can exchange genetic material between their genomes. The result is a recombinant or reassortant progeny with novel combinations of genes, potentially altering host range, virulence, or antigenicity.
Step-by-Step Solution:
Exclude host-mediated HGT terms (transformation/transduction) that describe bacterial gene transfer, not viral–viral recombination.Exclude transcription, which synthesizes RNA and does not equate to recombination.Identify coinfection with homologous genomes as the setting for recombination.Select the option describing simultaneous infection and homologous genomes.Verification / Alternative check:
Classic experiments with bacteriophages and observations in clinical virology (e.g., poliovirus, coronaviruses) document recombination during coinfection.
Why Other Options Are Wrong:
Transduction/transformation: bacterial processes, not viral–viral recombination mechanisms.
Transcription: necessary for gene expression but not recombination.
Common Pitfalls:
Confusing viral recombination with reassortment; both need coinfection, but reassortment applies to segmented genomes specifically.
Final Answer:
During simultaneous infection of a host cell by two viruses with homologous genomes
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