Rs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.
Amount = =Rs.8820
Amount of Rs. 100 for 1 year
when compounded half-yearly = Rs.[100*(1+3/100)^2]=Rs.106.09
Effective rate=(106.09-100)%=6.09%
P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount =
= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05
=> C.I. = 17126 - 15625 = Rs. 1901.05.
Let the sum be Rs. P.
Then,[p(1+10/100)2-p]=525
Sum =Rs.2500
S.I.= Rs.(2500*5*4)/100
= Rs. 500
The mathematical formula for calculating compound interest depends on several factors. These factors include the amount of money deposited called the principal, the annual interest rate (in decimal form), the number of times the money is compounded per year, and the number of years the money is left in the bank.
FV = Future value of the Deposit
p = Principal or Amount of Money deposited
r = Annual Interest Rate (in decimal form )
n = No of times compounded per year
t = time in years
= 5387.42
Shawn received an extra amount of (Rs.605 ? Rs.550) Rs.55 on his compound interest paying bond as the interest that he received in the first year also earned interest in the second year.
The extra interest earned on the compound interest bond = Rs.55
The interest for the first year =550/2 = Rs.275
Therefore, the rate of interest = = 20% p.a.
20% interest means that Shawn received 20% of the amount he invested in the bonds as interest.
If 20% of his investment in one of the bonds = Rs.275, then his total investment in each of the bonds = = 1375.
As he invested equal sums in both the bonds, his total savings before investing = 2 x 1375 =Rs.2750.
The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n
In this formula,
A is the amount at the end of the period of investment
P is the principal that is invested
r is the rate of interest in % p.a
And n is the number of years for which the principal has been invested.
In this case, it would turn out to be A =1500(1+20/100)^3
= 2592.
I. gives, Rate = 5% p.a.
II. gives, S.I. for 1 year = Rs. 600.
III. gives, sum = 10 x (S.I. for 2 years).
Now I, and II give the sum.
For this sum, C.I. and hence amount can be obtained.
Thus, III is redundant.
Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.
Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.
Thus,Rate = =5%
Thus, C.I. for 2 years and therefore, amount can be obtained.
Thus, I is redundant.
At first glance it might seem that this problem cannot be solved because we do not have enough
information. It can be solved as long as you double whatever amount you start with. If we start with
$100, then P = $100 and FV = $200.
FV=P(1+r/n)^nt
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