Amount of Rs. 100 for 1 year when compounded half-yearly |
] | = Rs. | [ | 100 x | ❨ | 1 + | 3 | ❩ | 2 | ] | = Rs. 106.09 |
100 |
∴ Effective rate = (106.09 - 100)% = 6.09%
P | ❨ | 1 + | 20 | ❩ | n | > 2P | ⟹ | ❨ | 6 | ❩ | n | > 2. |
100 | 5 |
Now, | ❨ | 6 | x | 6 | x | 6 | x | 6 | ❩ | > 2. |
5 | 5 | 5 | 5 |
So, n = 4 years.
C.I. = | [ | x | ❨ | 1 + | 4 | ❩ | 2 | - x | ] | = | ❨ | 676 | x | - x | ❩ | = | 51 | x. |
100 | 625 | 625 |
S.I. = | ❨ | x x 4 x 2 | ❩ | = | 2x | . |
100 | 25 |
∴ | 51x | - | 2x | = 1 |
625 | 25 |
⟹ x = 625.
Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109. .
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
Let sum=Rs.x
C.I. when compounded half yearly =
C.I. when compounded annually =
=> x=20000
Let the sum be Rs.P.then
P(1+R/100)^3=6690?(i) and P(1+R/100)^6=10035?(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.
For 1st year S.I =C.I.
Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200
i.e S.I on the principal for 1 year is Rs.200
Principle = = Rs.2500
Amount for 2 years, compounded half-yearly
C.I = Rs.424.64
Also,
Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64
Let each installment be Rs.x. Then,
(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.
=> x = 3430
Amount of each installment = Rs.3430
Thus I only or (II and III) give answer.
Correct answer is (D)
Copyright ©CuriousTab. All rights reserved.