Correct Answer: 21.6 m

Explanation:

Let AB be the observer and CD be the tower.

Draw BE ⊥ CD.

Then, CE = AB = 1.6 m,

      BE = AC = 20√3 m.

DE	= tan 30° =	1
BE		√3

⟹ DE =	20√3	m = 20 m.
	√3

∴ CD = CE + DE = (1.6 + 20) m = 21.6 m.

Correct Answer: 21.6 m

Correct Answer: 108 m

Explanation:

We know the rule that,

 

At particular time for all object , ratio of height and shadow are same.

 

Let the height of the pole be 'H'

 

Then

  18 8 = H 48

 

=> H = 108 m.

Correct Answer: 66.6 mts

Correct Answer: 12.5 cm

Explanation:

Let the required height of the building be x meter

More shadow length, More height(direct proportion)

Hence we can write as

(shadow length) 40.25 : 28.75 :: 17.5 : x
? 40.25 × x = 28.75 × 17.5
? x = 28.75 × 17.5/40.25
= 2875 × 175/40250
= 2875 × 7/1610
= 2875/230
= 575/46
= 12.5 cm