Principal = Rs.1000;
Amount = Rs.1331;
Rate = Rs.10%p.a.
Let the time be n years.Then
[1000(1+10/100)?n;]
= 1331.
= (1331/1000)
= (11/10)³
Therefore n = 3 years.
j=mi
I = ptr
Therefore, the total amount the owner received on January 17, 2001 was
$1295.57 + $10.47 = $1306.04
Amount
=Rs.[8000x(1+5/100)²]
= Rs.[8000 x 21/20x21/20]
= Rs.8820.
Sum =Rs.(50 x 100/2x5)
= Rs. 500.
Amount
=[Rs.500x(1+5/100)²]
=Rs(500x21/20x21/20).
=Rs. 551.25
C.I
= Rs. (551.25 - 500)
= Rs. 51.25
[15000 *(1+r/100)^2-15000]-(15000*r*2)/100=96
r=8
FV=P(1+r/n)^nt
F=P(1+i)^n
First find the present value of $3800,then compare present values:
M = p(1+i/4)^4n
i=j/m
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