Amount of Rs. 100 for 1 year
when compounded half-yearly = Rs.[100*(1+3/100)^2]=Rs.106.09
Effective rate=(106.09-100)%=6.09%
Amount = =Rs.8820
Rs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.
when interest is reckoned using compound interest, interest being compounded annually. The difference in the simple interest and compound interest for two years is on account of the interest paid on the first year's interest Hence 12% of simple interest = 90 => simple interest =90/0.12 =750.
As the simple interest for a year = 750 @ 12% p.a., the principal =750/0.12 = Rs.6250.
If the principal is 6250, then the amount outstanding at the end of 3 years = 6250 + 3(simple interest on 6250) + 3 (interest on simple interest) + 1 (interest on interest on interest) = 6250 +3(750) + 3(90) + 1(10.80) = 8780.80.
> 2P
Now, (6/5 x 6/5 x 6/5 x 6/5) > 2.
So, n = 4 years.
C.I =
594.5 =
% .
P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount =
= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05
=> C.I. = 17126 - 15625 = Rs. 1901.05.
Let the sum be Rs. P.
Then,[p(1+10/100)2-p]=525
Sum =Rs.2500
S.I.= Rs.(2500*5*4)/100
= Rs. 500
The mathematical formula for calculating compound interest depends on several factors. These factors include the amount of money deposited called the principal, the annual interest rate (in decimal form), the number of times the money is compounded per year, and the number of years the money is left in the bank.
FV = Future value of the Deposit
p = Principal or Amount of Money deposited
r = Annual Interest Rate (in decimal form )
n = No of times compounded per year
t = time in years
= 5387.42
Amount = P(1 + r/100)^t
Amount = 1875(1 + 4/100)^2
Amount = 1875(104/100)(104/100)
Amount = 2028
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