Area problems
- 1. If each side of a square is increased by 25%, find the percentage change in its area?
Options- A. 65.25
- B. 56.25
- C. 65
- D. 56 Also asked in: Bank Exams, Bank PO
Correct Answer: 56.25
Explanation:
let each side of the square be a , then area =
As given that The side is increased by 25%, then
New side = 125a/100 = 5a/4
New area =
Increased area=
Increase %= % = 56.25%
- 2. If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.
Options- A. 110
- B. 120
- C. 130
- D. 140 Also asked in: Bank Exams, Bank PO
Correct Answer: 120
Explanation:
let length = x and breadth = y then
2(x+y) = 46 => x+y = 23
x²+y² = 17² = 289
now (x+y)² = 23²
=> x²+y²+2xy= 529
=> 289+ 2xy = 529
=> xy = 120
area = xy = 120 sq.cm
- 3. If the radius of a circle is decreased by 50%, find the percentage decrease in its area.
Options- A. 55%
- B. 65%
- C. 75%
- D. 85% Also asked in: Bank Exams, Bank PO
Correct Answer: 75%
Explanation:
Let original radius = R.
New radius = =
Original area = and new area =
Decrease in area = = 75%
- 4. The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Options- A. 18
- B. 28
- C. 38
- D. 48 Also asked in: CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 18
Explanation:
(or)
Also,
= 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
- 5. A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
Options- A. 136
- B. 236
- C. 336
- D. 436 Also asked in: Bank Exams, Bank PO
Correct Answer: 336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC =
= = 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
- 6. The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
Options- A. 22%
- B. 33%
- C. 44%
- D. 55% Also asked in: Bank Exams, Bank PO
Correct Answer: 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = and Increased breadth =
New area =
The difference between the Original area and New area is:
Increase % = = 44%
- 7. A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Options- A. 30
- B. 40
- C. 50
- D. 60 Also asked in: Bank Exams, Bank PO
Correct Answer: 30
Explanation:
Let the side of the square(ABCD) be x meters.
Then, AB + BC = 2x metres.
AC = = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = = 30% (approx)
- 8. Find the ratio of the areas of the incircle and circumcircle of a square.
Options- A. 1:1
- B. 1:2
- C. 1:3
- D. 1:4 Also asked in: Bank Exams, Bank PO
Correct Answer: 1:2
Explanation:
Let the side of the square be x. Then, its diagonal =
Radius of incircle =
Radius of circum circle=
Required ratio =
- 9. A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be
Options- A. 7744
- B. 8844
- C. 5544
- D. 4444 Also asked in: Bank Exams, Bank PO
Correct Answer: 7744
Explanation:
length of wire =
= 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm
- 10. The ratio of the area of a square to that of the square drawn on its diagonal is
Options- A. 1:2
- B. 2;3
- C. 3:1
- D. 4:1 Also asked in: Bank Exams, Bank PO
Correct Answer: 1:2
Explanation:
ratio =
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