Cost of x metres = Rs. d.

Cost of 1 metre = Rs.(d/x)

Cost of y metres = Rs.[(d/x).y] = Rs.(yd/x)

Let the Required cost be X paise.  Less Weight , Less cost (Direct Proportion)

Therefore, 250 : 200 :: 60 : x

=> (250 * x) = (200 * 60)

=> x= 48

Let the required number of days be x.

Less cows, More days (Indirect Proportion)

Less bags, Less days (Direct Proportion)

$$\begin{gathered} c o w s 1 : 40 : 40 : x \\ b a g s 40 : 1 : 40 : x \\ \end{gathered}$$

1 x 40 x x = 40 x 1 x 40

=>  x = 40.

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$$\begin{gathered} w e a v e r s 4 : 8 } : 4 : x \\ d a y s 4 : 8 } : 4 : x \end{gathered}$$ 

4 x 4 x x = 8 x 8 x 4

=> x =  8 * 8 * 4 4 * 4

=> x = 16.

More Men, Less Hours {Indirect Proportion}

Less Days, More Hours {Indirect Proportion}

  m e n 15 : 10 d a y s 12 : 18 ? ? 6 : x

=> 15 * 12 * x = 10 * 18 * 6

=>x = 6

(Men 14 : 16) : (Hrs/Day 12 : 7) :: 48 : x
14 * 12 * x = 16 * 7 * 48 or x = 32

Let the required Price be Rs. X .Then, Lest toys , Less cost  (Direct Proportion) 

Therefore 6 : 5  :: 264.37 : x

=> 6 * x = 5 * 264.37

=> X= 220.308

Therefore,  Approximate price of 5 toys = Rs. 220

Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in,

1.14 ----- 1

52.0 ------?

  ? 52 1 . 14= 45.61 sec

There is a meal for 200 children. 150 children have taken the meal.

Remaining meal is to be catered to 50 children.

Now, 200 children = 120 men.

50 children = 120 200 50 =30men

Let the time required by x seconds.

Then, More cloth means More time (Direct Proportion)

So, 0.128 : 1 :: 25 : x

? x = 1 × 25 0 . 128 => x = 195.31

 So time will be approx 195 seconds