Profit (%) = 9.09 % = 1/11

Since the ratio of water and milk is  1 : 11,

Therefore the ratio of water is to mixture = 1:12

Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml

Let quantity of mixture be x liters.

Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid =  x 1 - y x n units, Where n = no of operations . 

So, Quantity of Milk =  x 1 - 6 x 2  

Given that, Milk : Water = 9 : 16 

=> Milk : (Milk + Water) = 9 : (9+16)

=> Milk : Mixture = 9 : 25 

 Therefore,  x 1 - 6 x 2 x = 9 25

=> x = 15 liters

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

         Milk             Water 

         74%             26%        (initially) 

         76%             24%        ( after replacement) 

  Left amount = Initial amount  1 - r e p l a c e d a m o u n t t o t a l a m o u n t 

   24  = 26 1 - 7 k

=> k = 91 

From the given data,

let the initial quantity of the mixture = 5x

Then,

$$\begin{gathered} 2 x - 16 3 x - 24 + 40 = 1 4 \\ 8 x - 64 = 3 x + 16 \\ 5 x = 80 \\ x = 16 lit \end{gathered}$$

Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

W i n e ( l e f t ) W a t e r ( a d d e d ) = 343 169

It means    W i n e ( l e f t ) W i n e ( i n i t i a l a m o u n t ) = 343 512   ? 343 + 169 = 512

Thus ,       

343 x = 512 x 1 - 15 K 3

  ? 343 512 = 7 8 3 = 1 - 15 k 3

=> K = 120

Thus the initial amount of wine was 120 liters.