Correct Answer: 30
Explanation:
Let total quantity of the mixture = x liters
Now 10 liters is removed
Amount of petrol removed = (3/5) × 10 = 6 liters
Amount of kerosene removed = (2/5) × 10 = 4 liters
Remaining:
10 liters of kerosene added, so:
Final kerosene = (2x/5 - 4) + 10 = (2x/5 + 6)
New ratio = 2:3
(3x/5 - 6) / (2x/5 + 6) = 2 / 3
Cross multiplying:
3(3x/5 - 6) = 2(2x/5 + 6) => (9x - 90) = (4x + 60) => 9x - 90 = 4x + 60 => 5x = 150 => x = 30
Answer: 30 liters
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