Difficulty: Easy
Correct Answer: LZS
Explanation:
Introduction / Context:
This is a letter-coding question where each letter is transformed using a fixed alphabet relation. The example indicates that every original letter is replaced by the letter immediately before it in the English alphabet (a backward shift of 1).
Given Data / Assumptions:
Concept / Approach:
Identify the shift from the example. Here, P→O and O→N clearly show a backward movement by 1 position. Apply the same backward shift to each character of the target word.
Step-by-Step Solution:
Rule: Replace each letter with the previous letter in the alphabet.
M → L (previous of M is L)
A → Z (previous of A is Z)
T → S (previous of T is S)
So MAT → LZS.
Verification / Alternative check:
Quick check using positions: M(13) becomes L(12), A(1) becomes Z(26), T(20) becomes S(19). All are exactly -1 shifts, confirming LZS.
Why Other Options Are Wrong:
NBU: implies forward shifting, not backward.
KXR: inconsistent or excessive backward shifts.
LZT: only two letters match the -1 rule.
MZS: keeps M unchanged, breaking the rule.
Common Pitfalls:
Forgetting that A shifts to Z, using +1 instead of -1, or mixing shifts per letter can lead to wrong codes.
Final Answer:
LZS
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