More Questions from Applied Mechanics

Centres of gravity (C.G.) of common plane figures Identify the incorrect statement about the location of the centre of gravity (centroid) of the listed shapes.

Civil Engineering Applied Mechanics Difficulty: Easy
Choose an option
  • A
    The C.G. of a circle is at its centre.
  • B
    The C.G. of a triangle is at the intersection of its medians.
  • C
    The C.G. of a rectangle is at the intersection of its diagonals.
  • D
    The C.G. of a semicircle is at a distance of r/2 from the centre.
  • E
    The C.G. of an ellipse is at the intersection of its axes.

Answer

Correct Answer: The C.G. of a semicircle is at a distance of r/2 from the centre.

Explanation

Introduction / Context:Remembering centroid locations of standard shapes is crucial for area moments, composite sections, and structural design. One of the statements below is intentionally wrong to test precise recall.

Given Data / Assumptions:

  • Plane laminae of uniform thickness and density.
  • Standard geometric shapes: circle, triangle, rectangle, semicircle, ellipse.

Concept / Approach:

For symmetric figures, the centroid lies at the intersection of symmetry axes. For semicircular area, the centroid lies along the axis of symmetry at a known distance from the circle’s centre, but it is not r/2.

Step-by-Step Solution:

(a) Circle: centroid at centre → correct.(b) Triangle: centroid at medians’ intersection → correct.(c) Rectangle: centroid at diagonal intersection → correct.(d) Semicircle: the correct distance from the circle centre to the area centroid is 4r/(3π) ≈ 0.424 r, not r/2 = 0.5 r → statement is incorrect.(e) Ellipse: centroid at intersection of major and minor axes → correct.

Verification / Alternative check:

Using tabulated centroid formulae, the semicircle’s area centroid from the base is 4r/(3π) relative to the circle centre along the symmetry line, confirming (d) is wrong.

Why Other Options Are Wrong:

Here only (d) is wrong; the others match standard results.

Common Pitfalls:

Confusing the centroid of a semicircular arc (2r/π) with that of a semicircular area (4r/(3π)); mixing distances from base versus from centre.

Final Answer:

The C.G. of a semicircle is at a distance of r/2 from the centre.

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