Difficulty: Easy
Correct Answer: At any point on the line of action of the force
Explanation:
Introduction / Context:
In engineering statics, the “principle of transmissibility” states that a force acting on a rigid body may be shifted anywhere along its line of action without altering the external mechanical effect (resultant force and moment about any point external to the body). This concept is fundamental to simplifying force systems and drawing free-body diagrams.
Given Data / Assumptions:
Concept / Approach:
The external effect of a force on a rigid body is fully described by the force vector and its moment about a reference point. Moving the force along its own line of action does not change the moment about any reference point outside the body, because the perpendicular distance to the line of action remains the same. Thus, equivalent systems result when the point of application is transmitted along the line of action.
Step-by-Step Solution:
Verification / Alternative check:
A quick check is to compute the moment M = r × F about a reference O using two different position vectors r1 and r2 to two points on the same line of action; their difference is parallel to F, so (r1 − r2) × F = 0, confirming equal moments.
Why Other Options Are Wrong:
Common Pitfalls:
Applying the principle to deformable bodies (where internal effects do change) or shifting a force off its line of action without adding a balancing couple (which would otherwise be needed to retain equivalence).
Final Answer:
At any point on the line of action of the force
Discussion & Comments