According to penetration theory (Higbie model), turbulent eddies intermittently contact the interface for an exposure time t_e. Which correlation relates the liquid-side mass transfer coefficient K_L to diffusivity D_AB and exposure time?

Difficulty: Easy

Correct Answer: K_L = 2 * (D_AB / (π * t_e))^0.5

Explanation:


Introduction:
Penetration theory explains unsteady diffusion into fluid elements that periodically renew the interface. It is a foundational concept for estimating K_L when interfacial renewal controls mass transfer in agitated or turbulent systems.


Given Data / Assumptions:

  • Fluid elements contact the interface for time t_e before being replaced.
  • Diffusion is unsteady during each contact.
  • Transport is characterized by molecular diffusivity D_AB.


Concept / Approach:
Solving the transient diffusion equation for exposure time t_e yields K_L proportional to the square root of D_AB / t_e. The constant 2 / √π arises from the analytical solution for a semi-infinite medium initially free of solute and suddenly exposed at the interface.


Step-by-Step Solution:

1) Assume elements renew at the interface every t_e seconds.2) Transient diffusion thickness grows as (D_AB * t)^0.5.3) Average flux over t_e leads to K_L ∝ (D_AB / t_e)^0.5.4) The Higbie solution gives K_L = 2 * (D_AB / (π * t_e))^0.5.5) Select the option with exponent 0.5 and coefficient form 2 / √π.


Verification / Alternative check:
Dimensional analysis confirms K_L units of length/time when D_AB has length^2/time and t_e is time, consistent with the square-root dependence.


Why Other Options Are Wrong:

  • Exponents 0.25 or 0.75 do not follow from the transient solution.
  • Linear dependence on D_AB / t_e is inconsistent with diffusion scaling.


Common Pitfalls:
Confusing penetration theory (unsteady) with film theory (steady) or surface renewal theory; while related, they use different characteristic parameters.


Final Answer:
K_L = 2 * (D_AB / (π * t_e))^0.5

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