OR gate behavior: is output HIGH only when both inputs are HIGH? Evaluate the statement about a two-input OR gate: “The output is HIGH only when both inputs are HIGH.” Determine whether this accurately describes OR logic.

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
Recognizing basic gate behavior is essential for reading and designing digital circuits. The statement given resembles the AND gate condition. This item checks whether you can distinguish OR from AND logic based on their truth conditions.



Given Data / Assumptions:

  • Standard positive-logic two-input gates.
  • Inputs and output are valid logic levels.
  • No special wiring (e.g., open-collector wired-OR) changes the logical definition.


Concept / Approach:
The OR operation outputs 1 if at least one input is 1. The only case that yields 0 is when all inputs are 0. The phrase “only when both inputs are HIGH” is the defining condition of an AND gate, not an OR gate. Therefore, the statement about an OR gate is incorrect.



Step-by-Step Solution:

Recall OR truth table: 0 OR 0 = 0; 1 OR 0 = 1; 0 OR 1 = 1; 1 OR 1 = 1.Compare to the statement: it describes 1 only for input pair (1,1).Note that OR also produces 1 for (1,0) and (0,1), contradicting the given claim.Conclude the statement is incorrect.


Verification / Alternative check:
Construct with diodes (wired-OR in positive logic) or use a logic simulator; observe that any HIGH input drives the output HIGH.



Why Other Options Are Wrong:

Correct: Would describe AND, not OR.Wired-OR / XOR distractors: Do not change basic OR truth; XOR is 1 only when inputs differ.


Common Pitfalls:
Confusing OR with AND because both yield 1 when both inputs are 1; the difference lies in the mixed input cases.



Final Answer:
Incorrect

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