Difficulty: Easy
Correct Answer: 50%
Explanation:
Introduction / Context:Duty cycle quantifies how long a periodic signal stays in its active (HIGH) state within one full period. For timing, PWM, and digital logic analysis, recognizing duty cycle values is fundamental.
Given Data / Assumptions:
Concept / Approach:An ideal square wave has symmetrical mark and space times. Therefore, time HIGH equals time LOW, each being T/2, yielding a 50% duty cycle. Rectangular waves with unequal durations are not “square” but “pulse” or “rectangular” waves.
Step-by-Step Solution:
Let time HIGH = T/2 for a square wave.Compute duty cycle = (T/2) / T * 100.Simplify to 50%.Confirm independence from frequency: the ratio holds at any period.Verification / Alternative check:Inspect a symmetric clock signal: the HIGH and LOW occupy equal horizontal spans on the oscilloscope; measurements across divisions confirm 50%.
Why Other Options Are Wrong:
10% / 25% / 100% / 0%: represent valid duty cycles for pulses, but they define rectangular waves, not ideal square waves.Common Pitfalls:Calling any periodic pulse “square.” Only the 50% case is strictly square. Be careful with definitions in specifications and timing diagrams.
Final Answer:50%
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