AND gate behavior — conditional pass-through: For a 2-input AND gate, if one input is fixed HIGH (logic 1), the output value equals the other input's logic level. Classify this statement.

Introduction / Context:Logic gate identities are foundational. This item checks whether learners recognize that a 2-input AND with one input tied HIGH acts as a buffer (passes the other input unchanged).

Given Data / Assumptions:

• Boolean definition: Y = A * B (AND).
• One input is fixed at logic 1 (HIGH).
• Standard positive logic is assumed.

Concept / Approach:If Y = A * B and A = 1, then Y = 1 * B = B. The gate becomes a conditional pass-through for B. This is a basic Boolean identity and underlies many enable/disable designs (an AND as an enable gate).

Step-by-Step Solution:

Verification / Alternative check:Truth table inspection with A = 1: If B = 0 → Y = 0; if B = 1 → Y = 1. Output equals B in all cases.

Why Other Options Are Wrong:

Common Pitfalls:Confusing AND with OR (where tying one input HIGH forces HIGH). Mixing up AND and NAND effects.

Final Answer:Correct