Difficulty: Easy
Correct Answer: 210
Explanation:
Introduction / Context:
This item checks rapid recognition of standard squares: 12^2 = 144, 13^2 = 169, 14^2 = 196. Spotting the outsider reinforces square benchmarks crucial for speed in classification tasks.
Given Data / Assumptions:
Concept / Approach:
Confirm equality to k^2 for small integers. If a value lies strictly between consecutive squares, it cannot be a perfect square.
Step-by-Step Solution:
144 = 12^2 → square.169 = 13^2 → square.196 = 14^2 → square.210 is between 14^2 = 196 and 15^2 = 225 → not a perfect square.
Verification / Alternative check:
Square-root estimation: sqrt(210) ≈ 14.49, not an integer, confirming non-square status.
Why Other Options Are Wrong:
Common Pitfalls:
Mistaking “close to a square” as sufficient. Only exact equality qualifies.
Final Answer:
210
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