Odd One Out — In 117–39, 164–41, 198–66, 213–71, three have the same quotient (first ÷ second). Identify the exception and justify.

Introduction / Context:Number-pair classification commonly uses division to reveal a hidden constant quotient. Your goal is to find the one pair that breaks the uniform quotient rule.

Given Data / Assumptions:

• Pairs: 117–39, 164–41, 198–66, 213–71.
• Interpret each as (a, b) and compute a / b.

Concept / Approach:If three quotients are equal and one is not, the latter is the odd one out.

Step-by-Step Solution:117 / 39 = 3.198 / 66 = 3.213 / 71 = 3.164 / 41 = 4.Thus, three pairs share quotient 3; one pair yields quotient 4.

Verification / Alternative check:Confirm by multiplication: 39*3 = 117; 66*3 = 198; 71*3 = 213; 41*3 = 123 ≠ 164 (indeed 41*4 = 164). This reconfirms the outlier.

Why Other Options Are Wrong:

• 117–39: follows quotient 3.
• 198–66: follows quotient 3.
• 213–71: follows quotient 3.

Common Pitfalls:Checking differences first does not isolate a single outlier (differences vary throughout). Division reveals the clean triad.

Final Answer:164-41