Difficulty: Medium
Correct Answer: 300
Explanation:
Introduction / Context: When coin counts are in a ratio but denomination values differ, total value equals the sum of (count * denomination) across types. Express counts using a common multiplier, compute value per “x”, and solve for x from the total value. Then extract the required count.
Given Data / Assumptions:
Concept / Approach: Let counts be x, 2x, 3x. Total value V (in paise) = 25x + 10*(2x) + 5*(3x). Simplify, equate to 6000, then solve for x. Finally, 5p coins = 3x.
Step-by-Step Solution:
Let counts = x (25p), 2x (10p), 3x (5p).Total value (paise) = 25x + 20x + 15x = 60x.Given value = ₹ 60 = 6000 paise ⇒ 60x = 6000 ⇒ x = 100.Number of 5p coins = 3x = 300.Verification / Alternative check: Actual value check: 25*100 + 10*200 + 5*300 = 2500 + 2000 + 1500 = 6000 paise = ₹ 60—consistent.
Why Other Options Are Wrong: 200, 180, 240, and 150 do not equal 3x with x = 100; they would produce a total value different from ₹ 60.
Common Pitfalls: Forgetting to convert rupees to paise; mixing value ratio with count ratio; or setting counts directly to 1, 2, 3 instead of x, 2x, 3x.
Final Answer: 300
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