Monostable multivibrator at rest — what is the typical Q output level before any trigger? Assume standard TTL/CMOS one-shot behavior where the output goes active for a timed pulse and then returns.
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ALOW
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B+5 V
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CSET
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DHIGH
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EHi-Z (tri-stated)
Answer
Correct Answer: LOW
Explanation
Introduction / Context:A monostable multivibrator has one stable state. When idle (no trigger), the output sits in that state; a trigger forces a temporary transition for a timed duration. This question checks default logic level knowledge for common one-shot outputs.
Given Data / Assumptions:
- Standard one-shot where the timed pulse is a HIGH pulse at Q.
- After timing, the device returns to its stable state.
Concept / Approach:Most textbook one-shots are depicted with Q LOW at rest and a positive-going pulse on trigger. Although some devices offer inverted outputs or alternative wiring, the conventional Q output idles LOW and pulses HIGH.
Step-by-Step Solution:
Identify the polarity of the pulse at Q: typically a HIGH pulse.Therefore, before trigger, Q must be LOW to allow a positive-going pulse.Verification / Alternative check:Diagrams for 555 monostable and 74x121/123 families commonly show Q LOW at rest, going HIGH for t = K * R * C, then returning LOW.
Why Other Options Are Wrong:
- +5 V or HIGH: that would imply a LOW-going pulse, not the typical default.
- SET: descriptive but not a logic level.
- Hi-Z: outputs are driven, not tri-stated, in basic one-shots.
Common Pitfalls:
- Confusing Q with /Q (inverted output), which would idle HIGH.
Final Answer:LOW