Difficulty: Easy
Correct Answer: all of the above
Explanation:
Introduction / Context:Classic RC charging exhibits exponential behavior for both capacitor voltage and loop current. The time constant tau = R * C sets the rate. After about 5 * tau, the capacitor is essentially fully charged for practical purposes. This question checks fundamental time-constant intuition.
Given Data / Assumptions:
Concept / Approach:Standard equations for charging are: Vc(t) = V_s * (1 − e^(−t/tau)) and I(t) = (V_s/R) * e^(−t/tau). Engineers often use 5 * tau as the practical "full-charge" time where Vc ≈ 99%.
Step-by-Step Solution:
tau = R * CVc(t) increases exponentially toward V_sI(t) decreases exponentially toward 0t ≈ 5 * tau gives Vc ≈ 0.993 * V_s, close enough to "charged"Verification / Alternative check:Plotting Vc(t) and I(t) vs time confirms the exponential rise and decay and the 5 * tau rule of thumb.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:all of the above
Discussion & Comments