Charging behavior of an RC network — which statements are true as a capacitor charges from a DC source? Assume a simple series R–C connected to a constant DC supply and select the best overall answer.

Difficulty: Easy

Correct Answer: all of the above

Explanation:


Introduction / Context:
Classic RC charging exhibits exponential behavior for both capacitor voltage and loop current. The time constant tau = R * C sets the rate. After about 5 * tau, the capacitor is essentially fully charged for practical purposes. This question checks fundamental time-constant intuition.


Given Data / Assumptions:

  • Series R–C driven by an ideal DC source
  • Initial capacitor voltage is zero
  • No leakage and constant R


Concept / Approach:
Standard equations for charging are: Vc(t) = V_s * (1 − e^(−t/tau)) and I(t) = (V_s/R) * e^(−t/tau). Engineers often use 5 * tau as the practical "full-charge" time where Vc ≈ 99%.


Step-by-Step Solution:

tau = R * CVc(t) increases exponentially toward V_sI(t) decreases exponentially toward 0t ≈ 5 * tau gives Vc ≈ 0.993 * V_s, close enough to "charged"


Verification / Alternative check:
Plotting Vc(t) and I(t) vs time confirms the exponential rise and decay and the 5 * tau rule of thumb.


Why Other Options Are Wrong:

  • Options a, b, c are all correct statements; thus "all of the above" is the best choice.
  • "None of the above" contradicts established RC theory.


Common Pitfalls:

  • Assuming charging is linear; it is exponential.
  • Equating 5 * tau with an exact limit; it is a practical guideline.


Final Answer:
all of the above

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