Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context: Multivibrators are classified as astable (oscillator), monostable (one-shot), and bistable (flip-flop). Only the astable and monostable rely inherently on R–C timing networks to create a time constant. A bistable has two stable states and no inherent timing component; it remains in a state until triggered to change.Given Data / Assumptions:
Concept / Approach: The hallmark of an R–C-based multivibrator is a timing interval determined by the product R*C (e.g., T ≈ 0.693 * R * C in common configurations). Bistables do not require such timing; they change state only upon an input trigger and then remain indefinitely. Therefore, calling a bistable an “R–C flip-flop” is inaccurate; it is a cross-coupled latch/flip-flop, not a timing circuit.Step-by-Step Solution:
Identify the function: bistable stores a binary state.Note absence of timing capacitor or charging path determining durations.Contrast with monostable/astable which depend on R–C time constants.Conclude statement is incorrect.Verification / Alternative check:
Datasheets for SR, JK, D flip-flops show no R–C timing in the core storage element.Why Other Options Are Wrong:
Correct: Would mischaracterize the role of R–C networks.True only in discrete transistor designs / True for CMOS not TTL: Technology does not change the defining behavior.Common Pitfalls:
Assuming any multivibrator involves R–C timing; only astable/monostable do.Confusing timing add-ons (like reset delays) with core bistable operation.Final Answer:
Incorrect
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