Work and Consumption – Mid-Day Meal planning: Food stocks are sufficient for 250 students for 33 days when each student receives 125 g per day. If 80 more students join (total 330) and the per-student serving remains 125 g, for how many days will the food last?

Introduction / Context:This is a standard “work (or stock) × time = constant” problem. When consumption per person is fixed, the total stock measured in person-days stays constant.

Given Data / Assumptions:

• Initial capacity: 250 students for 33 days, serving 125 g each (the gram figure cancels because it remains the same).
• New headcount: 330 students.
• Serving per student unchanged.

Concept / Approach:Use person-days: total stock = persons × days (at fixed per-person consumption).

Step-by-Step Solution:Total stock in person-days = 250 * 33.With 330 students, days available = (250 * 33) / 330.Compute: 250/330 = 25/33, so days = (25/33) * 33 = 25 days.

Verification / Alternative check:Scale up students by factor 330/250 = 1.32; therefore days scale down by 1/1.32 ≈ 0.7576; 0.7576 * 33 ≈ 25.

Why Other Options Are Wrong:20, 28, 30, and 22 days contradict the constant person-day relationship under identical per-student consumption.

Common Pitfalls:Using grams directly or changing serving size (which is stated constant) instead of using person-day balance.

Final Answer:25 days