Difficulty: Easy
Correct Answer: During simultaneous infection of a host cell by two viruses with homologous genomes
Explanation:
Introduction / Context:
Viruses evolve rapidly through mutation and recombination. Recombination requires co-presence of related genomes in the same host cell, enabling template switching or segment reassortment, depending on the virus type.
Given Data / Assumptions:
Concept / Approach:
When two related viruses infect the same cell, replication machinery can exchange genetic material between their genomes. The result is a recombinant or reassortant progeny with novel combinations of genes, potentially altering host range, virulence, or antigenicity.
Step-by-Step Solution:
Verification / Alternative check:
Classic experiments with bacteriophages and observations in clinical virology (e.g., poliovirus, coronaviruses) document recombination during coinfection.
Why Other Options Are Wrong:
Transduction/transformation: bacterial processes, not viral–viral recombination mechanisms.
Transcription: necessary for gene expression but not recombination.
Common Pitfalls:
Confusing viral recombination with reassortment; both need coinfection, but reassortment applies to segmented genomes specifically.
Final Answer:
During simultaneous infection of a host cell by two viruses with homologous genomes
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