Rashmi can complete a work in 16 days, Ravina in 12 4/5 (12.8) days, and Gitika in 32 days. They start together; Rashmi leaves after 4 days, and Ravina leaves 3 days before completion. How long does the work take in total?

Difficulty: Medium

Correct Answer: 9 days

Explanation:


Introduction / Context:
Another staged-contribution problem: all three begin, then Rashmi leaves early and, later, Ravina leaves before the end. Sum contributions over the appropriate intervals to solve for total time T.


Given Data / Assumptions:

  • Rashmi (R) = 1/16 per day; Ravina (V) = 1/12.8 = 5/64 per day; Gitika (G) = 1/32 per day.
  • All three work for the first 4 days; then only V and G until the last 3 days; finally only G for the last 3 days.


Concept / Approach:
Partition the timeline into three intervals and add their contributions. Let T be total days. Middle interval length is (T - 7) days.


Step-by-Step Solution:

Work in first 4 days = 4*(R+V+G) = 4*(1/16 + 5/64 + 1/32)= 4*(0.0625 + 0.078125 + 0.03125) = 0.6875Work in middle (T-7) days = (T-7)*(V+G) = (T-7)*(5/64 + 1/32) = (T-7)*0.109375Work in last 3 days = 3*G = 3*(1/32) = 0.09375Total = 0.6875 + 0.109375*(T-7) + 0.09375 = 10.109375*(T-7) = 0.21875 → T - 7 = 2 → T = 9 days


Verification / Alternative check:
Rough bounds: With three workers at start then fewer later, 9 days is plausible between the fastest joint and single-worker extremes.


Why Other Options Are Wrong:
They do not satisfy the partitioned-rate equality.


Common Pitfalls:
Misinterpreting “3 days before completion” as an isolated day rather than the last 3-day block without Ravina.


Final Answer:
9 days

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