Difficulty: Medium
Correct Answer: About 10 kb
Explanation:
Introduction / Context:Lambda vectors come in two major formats for cloning: insertion vectors and replacement vectors. Insertion vectors retain most of the λ genome and accept relatively small inserts. Replacement vectors remove a stuffer fragment to accommodate much larger inserts. Knowing these capacities is crucial when selecting the right vector for a given fragment size.
Given Data / Assumptions:
Concept / Approach:Because insertion vectors keep most of the λ genome intact, only a limited additional size can be added while keeping the total within packaging limits. In practice, inserts much above ~10 kb are not suitable for insertion vectors and should be moved to replacement formats.
Step-by-Step Solution:
Confirm vector class → insertion type retains bulk of λ DNA.Apply packaging window → little room left for extra DNA.Select the approximate maximum → around 10 kb insert size.Verification / Alternative check:Cloning guides for λ insertion vectors recommend inserts in the vicinity of several kilobases, and commonly state inefficiency beyond ~10 kb, whereas replacement vectors target ~15–20+ kb up to ~40 kb.
Why Other Options Are Wrong:
35 kb or 50 kb: typical of replacement or cosmid systems, not insertion vectors.18 kb: exceeds practical insertion-vector capacity.< 2 kb only: too restrictive; insertion vectors can clone several kb effectively.Common Pitfalls:Attempting large genomic fragments in insertion vectors and obtaining very low packaging or plaque yields.
Final Answer:About 10 kb.
Discussion & Comments