Microwave/waveguide fundamentals: match each statement to its correct concept. List I (Statement) List II (Concept) A. Ratio of maximum stored energy to energy lost per cycle 1. Propagation constant (β = ω / v_p) B. TEM mode in a lossless medium 2. Cutoff frequency is zero C. Ratio of angular frequency to phase velocity 3. Quality factor (Q) of a cavity or resonator D. Lowest-cutoff mode statement relevant to 4. Cylindrical (circular) waveguide context
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AA-3, B-2, C-4, D-1
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BA-2, B-3, C-1, D-4
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CA-3, B-2, C-1, D-4
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DA-2, B-3, C-4, D-1
Answer
Correct Answer: A-3, B-2, C-1, D-4
Explanation
Introduction / Context:This item links core microwave concepts: quality factor, propagation constant, cutoff, and waveguide modes. These fundamentals are repeatedly used in cavity design, transmission-line analysis, and mode identification.
Given Data / Assumptions:
- Lossless media are assumed unless stated otherwise.
- Propagation along z uses phase velocity v_p and angular frequency ω.
- Hollow circular waveguides support TE/TM modes; TEM does not propagate in single-conductor waveguides.
Concept / Approach:
Quality factor Q is defined as stored energy / energy lost per radian or per cycle (proportional definition used in exams). For TEM lines (e.g., coax), cutoff frequency is zero. The spatial phase constant β equals ω / v_p. Discussions about the lowest cutoff mode belong to specific waveguide geometries such as circular guides (TE11 is lowest).
Step-by-Step Solution:
A: “Ratio of stored to lost energy per cycle” ⇒ Q ⇒ A-3.B: TEM in a lossless medium has f_c = 0 ⇒ B-2.C: ω / v_p defines the phase constant β ⇒ C-1.D: “Lowest cutoff mode” is a property we discuss for circular waveguides (TE11) ⇒ D-4.Verification / Alternative check:
Standard formulas: β = ω / v_p; for TEM on ideal lines, β = ω√(L′C′) and no cutoff. For cavities/waveguides, Q = 2π * (energy stored / energy lost per cycle), consistent with statement A.
Why Other Options Are Wrong:
- Swapping Q with β confuses energy storage with phase progression.
- Assigning “cutoff zero” to non-TEM modes is incorrect for hollow waveguides.
Common Pitfalls:
Believing TEM can exist in a single-conductor hollow guide; TEM requires two conductors or a return path.
Final Answer:
A-3, B-2, C-1, D-4