Syllogism validation with set inclusion: if all trees in the park are flowering and some trees are dogwoods, assess the claim 'All dogwoods in the park are flowering trees'
Logical Reasoning
Logical Problems
Difficulty: Easy
Choose an option
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ATrue
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BFalse
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CUncertain (depends on season)
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DTrue only for mature dogwoods
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EFalse unless dogwoods are a majority
Answer
Correct Answer: True
Explanation
Given data
- All Trees_in_park ⊆ Flowering.
- Some Trees_in_park ∩ Dogwoods ≠ ∅.
Concept/Approach (why this method)
Universal inclusion: every member of the 'trees in the park' set is flowering; any subclass (e.g., dogwoods in the park) inherits this property.
Step-by-Step deduction1) Let D = {dogwoods in the park}. By premise, D ⊆ Trees_in_park.2) Since Trees_in_park ⊆ Flowering, transitivity gives D ⊆ Flowering.
Verification/Alternative
Venn diagram: place 'Trees' circle fully inside 'Flowering'; 'Dogwoods in park' is a sub-region within 'Trees', hence also inside 'Flowering'.
Common pitfalls
- Confusing 'some trees are dogwoods' with 'some dogwoods are flowering'—here all park trees are flowering, so all park dogwoods are flowering.
Final AnswerTrue