OR gate behavior (any-true condition): Which logic gate outputs a HIGH (logic “1”) when any one of its inputs is HIGH?

Difficulty: Easy

Correct Answer: OR gate

Explanation:


Introduction / Context:
Recognizing the canonical behavior of the OR gate is essential for control logic, enabling conditions, and combining multiple event signals. The key phrase is “any one input HIGH” causes the output to be HIGH, which defines the inclusive OR operation.


Given Data / Assumptions:

  • Standard positive logic levels (0 = LOW, 1 = HIGH).
  • Two or more inputs (the rule generalizes to N inputs).


Concept / Approach:
The inclusive OR function is defined by Y = A + B + … . The output is LOW only when all inputs are LOW. If any single input is HIGH, the sum evaluates to 1 and the output becomes HIGH. This is distinct from XOR, which is HIGH only when an odd number of inputs are HIGH, and from NOR, which outputs the complement of OR.


Step-by-Step Solution:

Evaluate OR for typical cases: (0,0) → 0; (1,0) → 1; (0,1) → 1; (1,1) → 1.Generalize: if any input = 1 → output = 1.Identify the gate that matches: OR gate.


Verification / Alternative check:
Truth table or Boolean algebra confirms that only the all-zero input combination yields a zero output. Hardware implementations in TTL/CMOS families (e.g., 7432 for OR) behave accordingly.


Why Other Options Are Wrong:

  • AND: Requires all inputs HIGH for a HIGH output.
  • NOR: Produces LOW when any input is HIGH (the inverse of OR).
  • NOT: Single-input inverter; does not implement multi-input any-true logic.


Common Pitfalls:
Confusing OR with XOR; remember inclusive OR allows multiple HIGH inputs without forcing the output LOW.


Final Answer:
OR gate

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