NAND–AND relationship: Assess the claim: “The output of a NAND gate equals the inverted output of an AND gate.” Determine if this statement is accurate for standard positive logic.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
NAND and AND are complementary operations. Many simplification techniques and universal-gate constructions rely on this exact relationship. Verifying the definition guards against common mistakes when reading mixed NAND/AND schematics or when replacing functions using universal NAND gates.


Given Data / Assumptions:

  • Positive logic, two inputs A and B.
  • Standard Boolean semantics; no electrical edge cases considered.


Concept / Approach:
By definition, NAND(A,B) = NOT(AND(A,B)). In symbolic form: Y_NAND = (A * B)′. Therefore, if Y_AND = A * B, then Y_NAND = NOT(Y_AND). This matches the statement precisely and is true independent of implementation technology (TTL, CMOS, ECL).


Step-by-Step Solution:

Compute AND output: Y_AND = A * B.Invert it: Y = NOT(Y_AND).Recognize this equals NAND truth table (only 11 maps to 0, others to 1).Therefore, the claim is correct.


Verification / Alternative check:
Truth table confirms: AND: 00→0, 01→0, 10→0, 11→1. NAND is the complement: 00→1, 01→1, 10→1, 11→0, which is exactly the inversion of AND’s output row by row.


Why Other Options Are Wrong:

  • Incorrect or technology-limited options: Boolean identity does not depend on output topology or supply voltage; it is logically universal.


Common Pitfalls:
Mixing up NAND with NOR (the complement of OR). Remember: NAND complements AND; NOR complements OR.


Final Answer:
Correct

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