Gate identification by requirement: “If both inputs must be ON (logic 1) for the output to be ON, which gate is described?” Determine whether the assertion correctly identifies an AND gate.

Introduction / Context:Being able to translate verbal behavior into a gate name enables quick schematic reading and functional reasoning. The classic description “output is 1 only when all inputs are 1” is the textbook definition of AND, used throughout digital design from enable signals to address decoding.

Given Data / Assumptions:

• Two-input gates in positive logic.
• “ON” corresponds to logic 1.
• We ignore electrical nuances like thresholds and timing.

Concept / Approach:AND implements multiplication of logic variables: Y = A * B. The output is high only for A=1 and B=1. For any input being 0, the product is 0. This matches the verbal requirement exactly and identifies the AND function unambiguously.

Step-by-Step Solution:

Verification / Alternative check:Boolean algebra: Y = A * B. De Morgan’s complement is NAND = (A * B)′, which flips the output for 11 only. This dual view reinforces the identification of AND from the verbal rule.

Why Other Options Are Wrong:

• Incorrect: Conflicts with the canonical definition.
• Negative logic / Schmitt / delay: Logic polarity, hysteresis, or timing do not change the truth table of AND.

Common Pitfalls:Confusing AND with OR (which is true for 11, 10, and 01). Remember: AND requires all inputs asserted; OR requires any input asserted.

Final Answer:Correct