In this letter analogy, MOQ is related to NLJ. Using the same pattern, which group of letters should complete the analogy MOQ : NLJ :: SUW : ?

Introduction / Context:
This analogy problem involves a less obvious but very important alphabetic transformation. The pair MOQ : NLJ can be cracked by recognising a mirror or reverse position mapping in the alphabet. Once this rule is found, it must be applied to SUW to obtain the correct related group. Such questions are slightly more advanced because they rely on the idea of alphabetical symmetry around the middle of the alphabet.

Given Data / Assumptions:
First pair: MOQ : NLJ. Second pair: SUW : ?. All letters are capital letters from A to Z. The same transformation is applied letter by letter.

Concept / Approach:
Instead of a simple addition or subtraction, this analogy uses a reverse position mapping based on the idea that the sum of positions of paired letters equals 27. For example, A and Z are paired, B and Y are paired, and so on. This is often described as reflecting letters in a mirror placed at the centre of the alphabet. We will first check that MOQ and NLJ follow this rule, and then apply it to SUW.

Step-by-Step Solution:
Step 1: Find the positions for MOQ. M = 13, O = 15, Q = 17. Step 2: Find the positions for NLJ. N = 14, L = 12, J = 10. Step 3: Check for mirror pattern based on sum 27. For M and N, 13 + 14 = 27. For O and L, 15 + 12 = 27. For Q and J, 17 + 10 = 27. So each letter in NLJ is the mirrored counterpart of the corresponding letter in MOQ when positions are summed to 27. Step 4: Apply the same mirror rule to SUW. S = 19, U = 21, W = 23. Mirror letter position = 27 minus given position. For S: 27 - 19 = 8, which is H. For U: 27 - 21 = 6, which is F. For W: 27 - 23 = 4, which is D. Thus SUW maps to HFD.

Verification / Alternative check:
We can further verify by mirroring HFD again. H is 8, so 27 - 8 = 19, which is S. F is 6, so 27 - 6 = 21, which is U. D is 4, so 27 - 4 = 23, which is W. This round trip confirms that SUW and HFD are perfect mirror pairs under the same transformation that links MOQ and NLJ. Therefore HFD is the only group consistent with the analogy rule.

Why Other Options Are Wrong:
IGE does not satisfy the property that the sum of positions with SUW letters equals 27 for each pair. CEG also fails the 27 sum rule and appears as a simple increasing sequence. KJI is a descending sequence near the middle of the alphabet, but it does not mirror SUW in the required way. TPR is another unrelated sequence and does not follow the mirror transformation from SUW.

Common Pitfalls:
Many learners initially search for fixed addition or subtraction patterns and become stuck when those fail. In such situations, it is useful to test mirror relationships, especially when the answers appear to move towards earlier letters in an irregular way. Remembering the 27 sum rule for mirrored letters (A with Z, B with Y, and so on) is a powerful tool for solving these more advanced letter analogies efficiently.

Final Answer:
The group of letters that correctly completes the analogy is HFD.