The length and breadth of a square are increased by 40% and 30% respectively. The area of the resulting rectangle exceeds the area of the square by
Aptitude
Area
Difficulty: Medium
Choose an option
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A35%
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B42%
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C62%
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D82%
Answer
Correct Answer: 82%
Explanation
### Concept & Net Percentage Change
When two dimensions of a 2D shape are increased by certain percentages, the net percentage change in area can be found using the effective percentage formula:
$$ \text{Net Change} = x + y + \frac{xy}{100} $$
### Step-by-Step Solution
1. Let the original side of the square be $10$ units.
2. The original area is $10 \times 10 = 100$ sq units.
3. The length is increased by $40\%$, so the new length is $10 + 4 = 14$ units.
4. The breadth is increased by $30\%$, so the new breadth is $10 + 3 = 13$ units.
5. The area of the resulting rectangle is $14 \times 13 = 182$ sq units.
6. The increase in area is $182 - 100 = 82$ sq units.
7. Since the original area is $100$, the percentage increase is exactly $82\%$.
### Exam Strategy & Shortcut
Apply the net percentage change formula directly:
Here, $x = +40$ and $y = +30$.
$\text{Net \% Change} = 40 + 30 + \frac{40 \times 30}{100}$
$= 70 + \frac{1200}{100}$
$= 70 + 12 = 82\%$
### Common Pitfall
Simply adding the two percentage increases ($40\% + 30\% = 70\%$) without accounting for the compounded effect of both dimensions increasing simultaneously.
### Final Answer
Therefore, the correct answer is **82%**.